iotests: remove the check-block.sh script

Now that meson directly invokes the individual I/O tests, the
check-block.sh wrapper script is no longer required.

Signed-off-by: Daniel P. Berrangé <berrange@redhat.com>
Reviewed-by: Thomas Huth <thuth@redhat.com>
Acked-by: Hanna Czenczek <hreitz@redhat.com>
Tested-by: Thomas Huth <thuth@redhat.com>
Message-Id: <20230303160727.3977246-9-berrange@redhat.com>
Signed-off-by: Alex Bennée <alex.bennee@linaro.org>
Message-Id: <20230315174331.2959-26-alex.bennee@linaro.org>

tests/check-block.sh

@@ -1,43 +0,0 @@
-#!/bin/sh
-
-if [ "$#" -eq 0 ]; then
-    echo "Usage: $0 fmt..." >&2
-    exit 99
-fi
-
-# Honor the SPEED environment variable, just like we do it for "meson test"
-format_list="$@"
-if [ "$SPEED" = "slow" ] || [ "$SPEED" = "thorough" ]; then
-    group=
-else
-    group="-g auto"
-fi
-
-skip() {
-    echo "1..0 #SKIP $*"
-    exit 0
-}
-
-if [ -z "$(find . -name 'qemu-system-*' -print)" ]; then
-    skip "No qemu-system binary available ==> Not running the qemu-iotests."
-fi
-
-cd tests/qemu-iotests
-
-# QEMU_CHECK_BLOCK_AUTO is used to disable some unstable sub-tests
-export QEMU_CHECK_BLOCK_AUTO=1
-export PYTHONUTF8=1
-# If make was called with -jN we want to call ./check with -j N. Extract the
-# flag from MAKEFLAGS, so that if it absent (or MAKEFLAGS is not defined), JOBS
-# would be an empty line otherwise JOBS is prepared string of flag with value:
-# "-j N"
-# Note, that the following works even if make was called with "-j N" or even
-# "--jobs N", as all these variants becomes simply "-jN" in MAKEFLAGS variable.
-JOBS=$(echo "$MAKEFLAGS" | sed -n 's/\(^\|.* \)-j\([0-9]\+\)\( .*\|$\)/-j \2/p')
-
-ret=0
-for fmt in $format_list ; do
-    ${PYTHON} ./check $JOBS -tap -$fmt $group || ret=1
-done
-
-exit $ret